Integrand size = 18, antiderivative size = 71 \[ \int \frac {\sqrt {a+b x} (A+B x)}{x^2} \, dx=\frac {(A b+2 a B) \sqrt {a+b x}}{a}-\frac {A (a+b x)^{3/2}}{a x}-\frac {(A b+2 a B) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{\sqrt {a}} \]
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Time = 0.02 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {79, 52, 65, 214} \[ \int \frac {\sqrt {a+b x} (A+B x)}{x^2} \, dx=-\frac {(2 a B+A b) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{\sqrt {a}}+\frac {\sqrt {a+b x} (2 a B+A b)}{a}-\frac {A (a+b x)^{3/2}}{a x} \]
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Rule 52
Rule 65
Rule 79
Rule 214
Rubi steps \begin{align*} \text {integral}& = -\frac {A (a+b x)^{3/2}}{a x}+\frac {\left (\frac {A b}{2}+a B\right ) \int \frac {\sqrt {a+b x}}{x} \, dx}{a} \\ & = \frac {(A b+2 a B) \sqrt {a+b x}}{a}-\frac {A (a+b x)^{3/2}}{a x}+\frac {1}{2} (A b+2 a B) \int \frac {1}{x \sqrt {a+b x}} \, dx \\ & = \frac {(A b+2 a B) \sqrt {a+b x}}{a}-\frac {A (a+b x)^{3/2}}{a x}+\frac {(A b+2 a B) \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x}\right )}{b} \\ & = \frac {(A b+2 a B) \sqrt {a+b x}}{a}-\frac {A (a+b x)^{3/2}}{a x}-\frac {(A b+2 a B) \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{\sqrt {a}} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.75 \[ \int \frac {\sqrt {a+b x} (A+B x)}{x^2} \, dx=\frac {\sqrt {a+b x} (-A+2 B x)}{x}-\frac {(A b+2 a B) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{\sqrt {a}} \]
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Time = 0.52 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.69
method | result | size |
pseudoelliptic | \(-\frac {\left (A b +2 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right ) x +\sqrt {a}\, \sqrt {b x +a}\, \left (-2 B x +A \right )}{\sqrt {a}\, x}\) | \(49\) |
derivativedivides | \(2 B \sqrt {b x +a}-\frac {A \sqrt {b x +a}}{x}-\frac {\left (A b +2 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{\sqrt {a}}\) | \(50\) |
default | \(2 B \sqrt {b x +a}-\frac {A \sqrt {b x +a}}{x}-\frac {\left (A b +2 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{\sqrt {a}}\) | \(50\) |
risch | \(2 B \sqrt {b x +a}-\frac {A \sqrt {b x +a}}{x}-\frac {\left (A b +2 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{\sqrt {a}}\) | \(50\) |
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Time = 0.23 (sec) , antiderivative size = 124, normalized size of antiderivative = 1.75 \[ \int \frac {\sqrt {a+b x} (A+B x)}{x^2} \, dx=\left [\frac {{\left (2 \, B a + A b\right )} \sqrt {a} x \log \left (\frac {b x - 2 \, \sqrt {b x + a} \sqrt {a} + 2 \, a}{x}\right ) + 2 \, {\left (2 \, B a x - A a\right )} \sqrt {b x + a}}{2 \, a x}, \frac {{\left (2 \, B a + A b\right )} \sqrt {-a} x \arctan \left (\frac {\sqrt {b x + a} \sqrt {-a}}{a}\right ) + {\left (2 \, B a x - A a\right )} \sqrt {b x + a}}{a x}\right ] \]
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Time = 10.46 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.32 \[ \int \frac {\sqrt {a+b x} (A+B x)}{x^2} \, dx=- \frac {A \sqrt {b} \sqrt {\frac {a}{b x} + 1}}{\sqrt {x}} - \frac {A b \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} \sqrt {x}} \right )}}{\sqrt {a}} + B \left (\begin {cases} \frac {2 a \operatorname {atan}{\left (\frac {\sqrt {a + b x}}{\sqrt {- a}} \right )}}{\sqrt {- a}} + 2 \sqrt {a + b x} & \text {for}\: b \neq 0 \\\sqrt {a} \log {\left (x \right )} & \text {otherwise} \end {cases}\right ) \]
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Time = 0.29 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.07 \[ \int \frac {\sqrt {a+b x} (A+B x)}{x^2} \, dx=\frac {1}{2} \, b {\left (\frac {4 \, \sqrt {b x + a} B}{b} + \frac {{\left (2 \, B a + A b\right )} \log \left (\frac {\sqrt {b x + a} - \sqrt {a}}{\sqrt {b x + a} + \sqrt {a}}\right )}{\sqrt {a} b} - \frac {2 \, \sqrt {b x + a} A}{b x}\right )} \]
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Time = 0.28 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.86 \[ \int \frac {\sqrt {a+b x} (A+B x)}{x^2} \, dx=\frac {2 \, \sqrt {b x + a} B b - \frac {\sqrt {b x + a} A b}{x} + \frac {{\left (2 \, B a b + A b^{2}\right )} \arctan \left (\frac {\sqrt {b x + a}}{\sqrt {-a}}\right )}{\sqrt {-a}}}{b} \]
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Time = 0.45 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.69 \[ \int \frac {\sqrt {a+b x} (A+B x)}{x^2} \, dx=2\,B\,\sqrt {a+b\,x}-\frac {\mathrm {atanh}\left (\frac {\sqrt {a+b\,x}}{\sqrt {a}}\right )\,\left (A\,b+2\,B\,a\right )}{\sqrt {a}}-\frac {A\,\sqrt {a+b\,x}}{x} \]
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